標題:
發問:
2 ZnS + 3O2 → 2ZnO + 2SO2 , 2ZnO + C → 2Zn + CO2 Suppose 48.6 g of zinc oxide are reduced with carbon. 1)what is the mass of zinc obtained? 2)what is the mass of C used for the reduction?
最佳解答:
1)what is the mass of zinc obtained? = 48.6 / (65.4 + 16) x 65.4 = 39.05 g 2)what is the mass of C used for the reduction? = 12 x 48.6 / (65.4 + 16) / 2 = 3.58 g
其他解答:
1) Mass of Zn in ZnO=[48.6 x 65.4/(65.4+16)]g=39.047g 2) Since carbon is oxidized to form carbon dioxide, therefore the mole ratio of carbon to oxygen=1 : 2. Mass of oxygen in ZnO=(48.6 - 39.047)g=9.553g So, mass of carbon used=(9.553/2)g=4.776g
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f4 chemistry question發問:
2 ZnS + 3O2 → 2ZnO + 2SO2 , 2ZnO + C → 2Zn + CO2 Suppose 48.6 g of zinc oxide are reduced with carbon. 1)what is the mass of zinc obtained? 2)what is the mass of C used for the reduction?
最佳解答:
1)what is the mass of zinc obtained? = 48.6 / (65.4 + 16) x 65.4 = 39.05 g 2)what is the mass of C used for the reduction? = 12 x 48.6 / (65.4 + 16) / 2 = 3.58 g
其他解答:
1) Mass of Zn in ZnO=[48.6 x 65.4/(65.4+16)]g=39.047g 2) Since carbon is oxidized to form carbon dioxide, therefore the mole ratio of carbon to oxygen=1 : 2. Mass of oxygen in ZnO=(48.6 - 39.047)g=9.553g So, mass of carbon used=(9.553/2)g=4.776g
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