標題:

Physics regarding heat

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發問:

1kg steam at 100C is mixed with 1 kg ice at 0C, assumed there is no heat loses to surroundings, what will be the final temperature. In what state will be the result outcome? (Take specific heat capacity as 4200 kg J, take latent of vapourization as 2.26*10^6 and fusion as 3.34*10^5)

最佳解答:

The energy released by 100C steam changes to 100C water =m(lv) =1(2.26*10^6) =2.26*10^6 J The energy required which 0C ice changes to 100C water =m(lf)+mc(deltaT) =3.34*10^5+(4200)(100) =754000 J
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