標題:

f.4 maths m1 (differentiation)

發問:

1. the value of f '(2) of f(x)= (2/x) - 1/√x - x^3 ans: (-100+√2)/8 find the derivative of each of the following functions with respect to x. 2. y=(x+1)(x+2)(x+3) ans: 3x^2+12x+11 3. y=(2x-1)(3x+4)(x+7) ans: 18x^2+94x+31 我想知個過程,最好詳細d,thx~

最佳解答:

1. the value of f '(2) of f(x)= (2/x) - 1/√x - x^3 f'(x) = -1*[2x^(-1-1)] - [-1/2(x^(-1/2-1))] - 3x^2 =-2/x^2 + 1/2x^(3/2) - 3x^2 f'(2) = (-100+√2)/8 find the derivative of each of the following functions with respect to x. 2. y=(x+1)(x+2)(x+3) = x^3+6x^2+11x+6 dy/dx= 3x^2+12x+11 3. y=(2x-1)(3x+4)(x+7) =6x^2+47x^2+31x-28 dy/dx=18x^2+94x+31

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