標題:

5條[中一]方程數學題 !!功課...急呀__!請入 ~~10點 ))

發問:

唔該"要詳細過程呀!! 1) 2(m-1) / 7 + 2 = 5m / 7 2) 3[4m - 5(m-1)] = 1 - 2m 3) 2x +3 / 8 -3 = 3 - 2x / 6 - 4 4) z-3 / 2 +5 = 2z + 1 / 3 - z +3 / 4 5) 2(2p + 1 + p +3 ) = 38 P.S :: / = 除 !! 唔該快D幫我呀 !! 更新: 3) 2x +3 3- 2x --------- - 3 = ---------- -4 8 6 4) z - 3 2z + 1 z + 3 ----- + 5 = --------- - --------- 5 3 4

最佳解答:

1) 2(m-1) / 7 + 2 = 5m / 7 2(m-1) + 14 = 5m....................一齊乘7 2m-2 + 14 = 5m 2m +12 = 5m 12 = 3m m=4 2) 3[4m - 5(m-1)] = 1 - 2m 3(4m - 5m +1) = 1 - 2m 3( - m +1) = 1 - 2m - 3m +3 = 1 - 2m 2 = m m =2 3) 2x +3 / 8 -3 = 3 - 2x / 6 - 4 2x +3 / 8 -3 = 3 - 2x / 6 - 4 48x +9 -72 = 72 -8x -96.....................一齊乘24 48x -63 = -8x -24 56x = 39 x=39/56 4) z-3 / 2 +5 = 2z + 1 / 3 - z +3 / 4 6(z-3) +60 = 24z +4 -12z +9..............一齊乘12 6z -18 +60 = 12z +13 6z +42 = 12z +13 6z=29 z=29/6 5) 2(2p + 1 + p +3 ) = 38 2( 3p +4 ) = 38 3p +4 = 19 3p=15 p=5 以上題目 全按照"先乘除,後加減" ,這鐵則運算 2008-11-18 19:06:21 補充: 2) 3[4m - 5(m-1)] = 1 - 2m 3(4m - 5m +5) = 1 - 2m 3( - m +5) = 1 - 2m - 3m +15 = 1 - 2m 14 = m m = 14

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其他解答:

1) 2(m-1) / 7+2 = 5m / 7 7[2(m-1) / 7 +2] = 7(5m/7) 2(m-1)+14 = 5m 2m-2+14 = 5m 2m+12 = 5m 12 = 5m-2m 12 = 3m m = 12/3 m = 4 2) 3[4m - 5(m-1)] = 1 - 2m 3(4m - 5m + 5) = 1 - 2m 12m - 15m + 15 = 1-2m 15-3m = 1-2m 15-1 = 3m-2m m = 14 3), 4) 我不太肯定你的括號是不是對的 你是否肯定題目是2x + (3/8) - 3 = 3 - (2x/6) - 4和 z - (3/2) + 5 = 2z + (1/3) - z + (3/4)??? 待會再補充. 5) 2(2p + 1 + p +3 ) = 38 2p + 1 + p + 3 = 19 3p = 19-1-3 3p = 15 p = 5|||||I can help u 2 of them!!!~ 2) 3[4m - 5(m-1)] = 1 - 2m 12m-15m+3=1-2m 2=1m m=2 5) 2(2p + 1 + p +3 ) = 38 4p+2+2p+6=38 6p+8=38 6p=30 p=5 2008-11-18 19:08:19 補充: 上面001個人 no.5 is wrong!!!! the correct answer is 5!!!!
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