標題:
simplify the followings
發問:
此文章來自奇摩知識+如有不便請留言告知
Question 1 (m^3-m /4m^2) / ( 2m-2/m^8) Question 2 (9t/2t-5) x (8t-20/12) /( 8t^4/36) p.s Assume no denominator is equal to zero
最佳解答:
Question 1 (m^3-m /4m^2) / ( 2m-2/m^8) =[m(m^2-1)/4m^2]/2( m-1/m^8) =[(m+1)(m-1)/4m]/2(m-1/m^8) =[(m+1)/4m]/(2/m^8) =(m+1)m^8/2(4m) =(m+1)m^7/8 Question 2 (9t/2t-5) x (8t-20/12) /( 8t^4/36) =(9t/2t-5) x 4(2t-5/12) /( 2t^4/9) =(9t) x 4(1/12) /( 2t^4/9) =(9t)(1/3)(9)/2t^4 =27t/2t^4 =27/2t^3
其他解答:
文章標籤
全站熱搜
留言列表
