標題:
M2 Trigonometric functions
發問:
1. It is given that tanθ = (-9/40) and 3π/2
最佳解答:
tanθ = (-9/40) cosθ=40/41 sinθ=-9/41 (a) sin(3π/2 + θ) = -cos θ = -40/41 (b) cos(π+θ) =-cosθ =-40/41 (c) sin(θ-13π) =sin(θ-π) =-sinθ =9/41 2. cosθ = (-5/13) sinθ=-12/13 tanθ=12/5 13sin(θ-270°) / [12cosec(-θ) + 5tan(180°+θ) ] =13cosθ / [12(-cscθ) + 5tanθ ] =13(-5/13) / [12(-(-13/12)) + 5(12/5) ] =-5 / [13 +12] =-5 / [25 ] =-1/ 5 2015-01-13 16:54:07 補充： tan(7π/2 - θ) =tan(π/2 - θ) =cotθ = -40/9
其他解答:
此文章來自奇摩知識+如有不便請留言告知
文章標籤
全站熱搜
留言列表
