標題:
Physics
發問:
最佳解答:
Decrease in temperature of copper block = 100 – 33 = 67℃ Assume no energy is lost to the surroundings, By the law of conservation of energy Heat gained by water = Heat loss by copper (0.2)(4200)(33﹣25) = 0.3c(67) 6720 = 20.1c c = 334 Jkg-1K-1 (correct to 3 significant figures) ∴the specific heat capacity of the copper block is 334 Jkg-1K-1
其他解答:
0.3 x c x (100-33)=0.2 x 4200 x(33-25) c=334 copper原本在boiling water 中,所以是100度 copper放既能量=water叫既能量 所以得到上面的數式
Physics
發問:
此文章來自奇摩知識+如有不便請留言告知
A copper block of mass 0.3 kg is placed in boiling water for a while .It is then transferred to water of mass 0.2kg in a polystyrene . The temperature of water in the cup increases from 25度 to 33度. 1.(a) Calculate the specific heat capacity of copper (,correct to 3 significant figures.)最佳解答:
Decrease in temperature of copper block = 100 – 33 = 67℃ Assume no energy is lost to the surroundings, By the law of conservation of energy Heat gained by water = Heat loss by copper (0.2)(4200)(33﹣25) = 0.3c(67) 6720 = 20.1c c = 334 Jkg-1K-1 (correct to 3 significant figures) ∴the specific heat capacity of the copper block is 334 Jkg-1K-1
其他解答:
0.3 x c x (100-33)=0.2 x 4200 x(33-25) c=334 copper原本在boiling water 中,所以是100度 copper放既能量=water叫既能量 所以得到上面的數式
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