標題:
Probability
發問:
May and Joe play a game. Probability that May wins, Joe wins and tie are 1/2, 1/3 and 1/6 respectively. They play the game 3 times. Find the probability that May and Joe win alternatively. [Ans. 5/36]
最佳解答:
There are two possible squences: MJM, JMJ, J stands for Joe win and M stands for May wins. P(MJM) = 1/2*1/3*1/2 = 1/12 P(JMJ) = 1/3*1/2*1/3 = 1/18 so P(May and Joe win alternatively) = 1/12 + 1/18 = 5/36
Probability
發問:
May and Joe play a game. Probability that May wins, Joe wins and tie are 1/2, 1/3 and 1/6 respectively. They play the game 3 times. Find the probability that May and Joe win alternatively. [Ans. 5/36]
最佳解答:
There are two possible squences: MJM, JMJ, J stands for Joe win and M stands for May wins. P(MJM) = 1/2*1/3*1/2 = 1/12 P(JMJ) = 1/3*1/2*1/3 = 1/18 so P(May and Joe win alternatively) = 1/12 + 1/18 = 5/36
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