標題:
Chem:Concentration of solution
發問:
最佳解答:
a) the density of a.68 ammonia is 0.68 g cm^-3 density = mass / volume 1dm^3=1000cm^3 mass = 0.68 x 1000 = 680g this is the total mass of solution in 1 dm^3 approximately 34% of ammonia by mass 680x 0.34=231.2g b) mol = mass/ gram formula mass = 231.2/17 = 13.6mol C) mol = concentration x volume (Mol=CV) V=Mol/C V=13.6/1 = 13.6dm^3
其他解答:
Chem:Concentration of solution
發問:
此文章來自奇摩知識+如有不便請留言告知
需要計算步驟A commercial ammonia called '0.68 ammonia' has a density of 0.68 g cm^-3 amd contains approximately 34% of ammonia by mass.a) Calculate the mass of ammonia present in 1 dm^3 of the solution of this commercial ammonia.b) Calculate the molarity of this solution.c) Calculate the volume of... 顯示更多 需要計算步驟 A commercial ammonia called '0.68 ammonia' has a density of 0.68 g cm^-3 amd contains approximately 34% of ammonia by mass. a) Calculate the mass of ammonia present in 1 dm^3 of the solution of this commercial ammonia. b) Calculate the molarity of this solution. c) Calculate the volume of distilled water added if the solution has to be diluted to 1 mol dm^-3. (Relative atomic masses: H = 1.0, N = 14.0)最佳解答:
a) the density of a.68 ammonia is 0.68 g cm^-3 density = mass / volume 1dm^3=1000cm^3 mass = 0.68 x 1000 = 680g this is the total mass of solution in 1 dm^3 approximately 34% of ammonia by mass 680x 0.34=231.2g b) mol = mass/ gram formula mass = 231.2/17 = 13.6mol C) mol = concentration x volume (Mol=CV) V=Mol/C V=13.6/1 = 13.6dm^3
其他解答:
文章標籤
全站熱搜
留言列表
