標題:
statistics
發問:
如果有三個人比賽: A,B,C P(A beats B)=0.041 P(C beats A)=0.35 P(A beats B)=0.94 咁P(C wins)=?????
最佳解答:
There are two possible events that will lead to C's victory: 1. C beats B and B beats A. 2. C beats A and A beats B. For event 1, the probability is: P(C beats B) P(B beats A) = 0.94 0.959 = 0.90146 For event 2, the probability is: P(C beats A) P(A beats B) = 0.35 0.041 = 0.01435 Since the 2 events are mutually exclusive, so P(C wins) = 0.90146 + 0.01435 = 0.91581
statistics
發問:
如果有三個人比賽: A,B,C P(A beats B)=0.041 P(C beats A)=0.35 P(A beats B)=0.94 咁P(C wins)=?????
最佳解答:
There are two possible events that will lead to C's victory: 1. C beats B and B beats A. 2. C beats A and A beats B. For event 1, the probability is: P(C beats B) P(B beats A) = 0.94 0.959 = 0.90146 For event 2, the probability is: P(C beats A) P(A beats B) = 0.35 0.041 = 0.01435 Since the 2 events are mutually exclusive, so P(C wins) = 0.90146 + 0.01435 = 0.91581
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