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F. 2 Maths-Factorization by using identities(兩題=+40點)

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F. 2 Maths-Questions about factorization by using identities (最佳解答取40點) Factorize the following expressions. 1. b^2+ab+1/4a^2 2. 3+9/a^2+a^2/4 Please show your working steps clearly and explain them briefly. Tell me about the techniques to deal with these problems too if you can.

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最佳解答:

1)b^2+ab+1/4a^2 =^2+2(a/2)(b)+(a/2)^2 =b-0.5a)^2 其實一眼睇到=.=" 2)3+9/a^2+a^2/4 (3/a)^2+2(3/a)+(a/2)^2 =(3/a+a/2)^2 2006-12-19 22:40:45 補充： 有d字唔見左1)b^2 ab 1/4a^2=b^2 2(a/2)(b) (a/2)^2=(b-0.5a)^2 其實一眼睇到=.="2)3 9/a^2 a^2/4(3/a)^2 2(3/a) (a/2)^2=(3/a a/2)^2都係一眼就睇到=.="其實d step係睇到之後再想出來

其他解答:

1. b^2+ab+1/4a^2 <-----將1/4a^2 變做2次方的format =b^2+ab+(a/2)^2<------用恆等式計 =b^2+ 2(b)(a/2) + (a/2)^2 =(b+1/2a)^2 2.3+9/a^2+a^2/4 =9/a^2+3+a^2/4<------排返正確2次方的formay先 =(3/a)^2+3+(a/2)^2<--------抽2次方 =(3/a)^2 + 2(3/a)(a/2) + (a/2)^2 <----------用恆等式計 =(3/a +a/2)^2 希望幫到你..=)|||||1) (b+1/2a)(b+1/2a) =(b+1/2a)^2 2) 3+36/4a^2+a^4/4a^2=3+9/a^2+a^2/4 (36+a^4)/4a^2+3=3+9/a^2+a^2/4 (36+a^4)/4a^2=9/a^2+a^2/4 (36+a^4)= 2006-12-19 22:46:37 補充： sor.......第2題因為冇紙所以好難睇黎計= ="而且我唔知係factorization.......上面果個計得岩....!~|||||1. b^2+ab+1/4a^2 <-----打1/4a^2 抽個2次方出哩 =b^2+ab+(a/2)^2<------用恆等式計 =(b+a/2)^2 2.3+9/a^2+a^2/4 =9/a^2+3+a^2/4<------排返正確位置 =(3/a)^2+3+(a/2)^2<--------抽2次方,並用恆等式 =(3/a +a/2)^2
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