標題:
F4 Maths
1.In drawing a number from 1 to 20,find the probability that the number is (1) odd,(2) divisible by 3 ,(3) odd and divisible by 3 ,(4) odd or divisible by 3 ,2.In a game,a player tosses two fair coins,He wins $10 if 2 heads occur,$5 if 1head occur. He loses $24 if no heads occur. Calculate his expected... 顯示更多 1. In drawing a number from 1 to 20,find the probability that the number is (1) odd, (2) divisible by 3 , (3) odd and divisible by 3 , (4) odd or divisible by 3 , 2. In a game,a player tosses two fair coins,He wins $10 if 2 heads occur,$5 if 1 head occur. He loses $24 if no heads occur. Calculate his expected gain for each game. 詳細解釋... 謝謝..謝謝.. 更新: 關於Probabilities
最佳解答:
1)a) ∵ odd no. includes: 1, 3, 5,7, 9, 11, 13, 15, 17, 19 <-(total 10 no.)a) ∴ P(odd)= 10/20 = 1/2b) ∵ no.that is divisible by 3 includes: 3,6, 9, 12, 15, 18 <-(total 6 no.)b) ∴ P(divisible by 3) = 6/20 = 3/10c) ∵ no.that is odd and divisible by 3 includes: 3, 9, 15 <- (total 3no.)c) ∴ P(odd and divisible by 3) = 3/20d) ∵ no.that is odd or divisible by 3 includes:d) ∵ 1, 3, 5, 6, 7, 9,11, 12, 13, 15, 17, 18, 19 <-(total 13) d) ∴ P(odd or divisible by 3) = 13/20 2) ∵ Allpossible outcome include: HH, HT, TH, TT <-(total 4)2) ∴ Expectedgain2) ∴= 10P(2H)+ 5P(1H) - 24P(0H)2) ∴= 10(1/4)+ 5(2/4) - 24(1/4)2) ∴= -$1 p.s.H = Head, T = Tail. 希望幫到你，不明白的話可再補充問題!
其他解答:
1。 在繪製從1數到20，發現數量的概率 （1）奇數， （2）被3整除， （3）奇數和3整除， （4）奇或3整除， 2。 一個球員在一場比賽中，擲兩個公平的硬幣，他贏得$ 10，如果出現2頭，5元，如果1 前往發生。他失去了24美元，如果沒有頭發生。計算其預期收益 每場比賽。|||||(2) There are totally 20 numbers. Numbers divisible by 3 : 3, 6, 9, 12, 15, 18 Number of numbers divisible by 3 = 6 P(the number is divisible by 3) = 6/20 = 3/10 (3) There are totally 20 numbers. Numbers that are odd and divisible by 3 : 6, 12, 18 Number of numbers that are odd and divisible by 3 = 3 P(the number is odd and divisible by 3) = 3/20 (4) There are totally 20 numbers. Numbers that are odd or divisible by 3 : 2, 3, 4, 6, 8, 9, 10, 12, 14, 15, 16, 18,20 Number of numbers that are odd and divisible by 3 = 13 P(the number is odd or divisible by 3) = 13/20 2. P(2 heads) = P(head, head) = (1/2) * (1/2) = 1/4 P(1 head) = P(head, tail) + P(tail, head) = (1/2) * (1/2) + (1/2) * (1/2) = 1/2 P(no head) = P(tail, tail) = (1/2) * (1/2) = 1/4 Expected gain for each game) = $10 * (1/4) + $5 * (1/2) - $24 * (1/4) = $(2.5 + 2.5 - 6) = -$1 (Expected loss for each game = $1)
F4 Maths
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發問:1.In drawing a number from 1 to 20,find the probability that the number is (1) odd,(2) divisible by 3 ,(3) odd and divisible by 3 ,(4) odd or divisible by 3 ,2.In a game,a player tosses two fair coins,He wins $10 if 2 heads occur,$5 if 1head occur. He loses $24 if no heads occur. Calculate his expected... 顯示更多 1. In drawing a number from 1 to 20,find the probability that the number is (1) odd, (2) divisible by 3 , (3) odd and divisible by 3 , (4) odd or divisible by 3 , 2. In a game,a player tosses two fair coins,He wins $10 if 2 heads occur,$5 if 1 head occur. He loses $24 if no heads occur. Calculate his expected gain for each game. 詳細解釋... 謝謝..謝謝.. 更新: 關於Probabilities
最佳解答:
1)a) ∵ odd no. includes: 1, 3, 5,7, 9, 11, 13, 15, 17, 19 <-(total 10 no.)a) ∴ P(odd)= 10/20 = 1/2b) ∵ no.that is divisible by 3 includes: 3,6, 9, 12, 15, 18 <-(total 6 no.)b) ∴ P(divisible by 3) = 6/20 = 3/10c) ∵ no.that is odd and divisible by 3 includes: 3, 9, 15 <- (total 3no.)c) ∴ P(odd and divisible by 3) = 3/20d) ∵ no.that is odd or divisible by 3 includes:d) ∵ 1, 3, 5, 6, 7, 9,11, 12, 13, 15, 17, 18, 19 <-(total 13) d) ∴ P(odd or divisible by 3) = 13/20 2) ∵ Allpossible outcome include: HH, HT, TH, TT <-(total 4)2) ∴ Expectedgain2) ∴= 10P(2H)+ 5P(1H) - 24P(0H)2) ∴= 10(1/4)+ 5(2/4) - 24(1/4)2) ∴= -$1 p.s.H = Head, T = Tail. 希望幫到你，不明白的話可再補充問題!
其他解答:
1。 在繪製從1數到20，發現數量的概率 （1）奇數， （2）被3整除， （3）奇數和3整除， （4）奇或3整除， 2。 一個球員在一場比賽中，擲兩個公平的硬幣，他贏得$ 10，如果出現2頭，5元，如果1 前往發生。他失去了24美元，如果沒有頭發生。計算其預期收益 每場比賽。|||||(2) There are totally 20 numbers. Numbers divisible by 3 : 3, 6, 9, 12, 15, 18 Number of numbers divisible by 3 = 6 P(the number is divisible by 3) = 6/20 = 3/10 (3) There are totally 20 numbers. Numbers that are odd and divisible by 3 : 6, 12, 18 Number of numbers that are odd and divisible by 3 = 3 P(the number is odd and divisible by 3) = 3/20 (4) There are totally 20 numbers. Numbers that are odd or divisible by 3 : 2, 3, 4, 6, 8, 9, 10, 12, 14, 15, 16, 18,20 Number of numbers that are odd and divisible by 3 = 13 P(the number is odd or divisible by 3) = 13/20 2. P(2 heads) = P(head, head) = (1/2) * (1/2) = 1/4 P(1 head) = P(head, tail) + P(tail, head) = (1/2) * (1/2) + (1/2) * (1/2) = 1/2 P(no head) = P(tail, tail) = (1/2) * (1/2) = 1/4 Expected gain for each game) = $10 * (1/4) + $5 * (1/2) - $24 * (1/4) = $(2.5 + 2.5 - 6) = -$1 (Expected loss for each game = $1)
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