標題:
mathz of f.2
1)Make the letter in the brackets the subject of each of the following formulae. a)p/3+11=4[(q/2)+1] * [q] b)(10/u)+(1/v)=9/u *[v] 更新: c) w=1-2r/r+2 *[r] d) L=(m/n)+(1/m) *[n]
最佳解答:
a)p/3+11=4[(q/2)+1] * [q] p/3+11=2q+1 p/3+10=2q q = (p/3+10)/2 q = (p/3+30/3)/2 q = (p+30)/2 b)(10/u)+(1/v)=9/u *[v] 1/v = -1/u v = -u c) w=1-2r/r+2 *[r] wr+2w = 1-2r wr+2r = 1-2w r(w+2) = 1-2w r = (1-2w)/(w+2) d) L=(m/n)+(1/m) *[n] L = (m^2+n)/(mn) Lmn = m^2+n Lmn-n = m^2 n(Lm-1) = m^2 n = m^2/(Lm-1)
其他解答:
mathz of f.2
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發問:1)Make the letter in the brackets the subject of each of the following formulae. a)p/3+11=4[(q/2)+1] * [q] b)(10/u)+(1/v)=9/u *[v] 更新: c) w=1-2r/r+2 *[r] d) L=(m/n)+(1/m) *[n]
最佳解答:
a)p/3+11=4[(q/2)+1] * [q] p/3+11=2q+1 p/3+10=2q q = (p/3+10)/2 q = (p/3+30/3)/2 q = (p+30)/2 b)(10/u)+(1/v)=9/u *[v] 1/v = -1/u v = -u c) w=1-2r/r+2 *[r] wr+2w = 1-2r wr+2r = 1-2w r(w+2) = 1-2w r = (1-2w)/(w+2) d) L=(m/n)+(1/m) *[n] L = (m^2+n)/(mn) Lmn = m^2+n Lmn-n = m^2 n(Lm-1) = m^2 n = m^2/(Lm-1)
其他解答:
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