標題:

中一一元一次方程(急)(要列式)(4題)(15點)

發問:

1. 5z+7 = 3z-11 2. 4q+2÷2 = q+4 3. 10-a÷3 = a+10÷2 4. 1-a÷8 = a-12÷3

最佳解答:

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您好,我是 lop,高興能解答您的問題。 (1) 5z + 7 = 3z - 11 5z - 3z = -11 - 7 2z = -18 z = -18 ÷ 2 z = -9 (2) (4q+2) ÷ 2 = q + 4 4q + 2 = 2(q+4) 4q + 2 = 2q + 8 4q - 2q = 8 - 2 2q = 6 q = 6 ÷ 2 q = +3 (3) Case 1 : (10-a) ÷ 3 = (a+10) ÷ 2 6(10-a) ÷ 3 = 6(a+10) ÷ 2 2(10-a) = 3(a+10) 20 - 2a = 3a + 30 20 - 30 = 3a + 2a -10 = 5a a = -10 ÷ 5 a = -2 Case 2 : 10 - a÷3 = (a+10) ÷ 2 6(10-a÷3) = 6(a+10) ÷ 2 60 - 2a = 3(a+10) 60 - 2a = 3a + 30 60 - 30 = 3a + 2a 30 = 5a a = 30 ÷ 5 a = +6 (4) (1-a) ÷ 8 = (a-12) ÷ 3 24(1-a) ÷ 8 = 24(a-12) ÷ 3 3(1-a) = 8(a-12) 3 - 3a = 8a - 96 3 + 96 = 8a + 3a 99 = 11a a = 99 ÷ 11 a = +9

其他解答:

1. 5z-3z=-11-7 2z=-18 z=-9 2. 4q+1(因為2/2=1)=q+4 4q-q=4-1 3q=3 q=1 3.10-(a/3)=a+5 10-a/3=a+5 10-5=a+a/3 5=4a/3 5x3=4a 15=4a a=3.75 4. 1-(a/8)=a-4 1x8-(a/8)x8=ax8-4x8 8-a=8a-32 40=9a a=4.444444 第4題不太確定.如有大大計到整數,請通知小弟|||||1. 5z+7 = 3z-11 5z-3z=-11-7 2z = -18 z=-9 2. 4q+2÷2 = q+4 4q+1= q+4 4q-q=4-1 3q=3 q=1
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