標題:
請問可否列出如何計算出X值的步驟?
發問:
(1.2926 - X) x 100000 = 2475/ X 更新: i'm just studying form 1, please show me the details. Thanks~
(1.2926 - X) x 100000 = 2475/ X 1.2926-X=0.02475/X 1.2926X-X^2=0.02475 X^2-1.2926X+0.02475=0 X=1.273 or X=0.0194 if you are higher than Form 3, i think you could understand my steps, if not, please ask for more detail steps. 2007-01-27 19:50:30 補充： for this question, if not using programme of calculator, the only way to solve is using this formula:if ax^2 bx c=0, x=(-b 開方[b^2-4ac])/2a or x=(-b-開方[b^2-4ac])/2ain this case, a=1, b=-1.2926, c=0.02475so X=1.273 or X=0.0194 2007-01-27 19:50:47 補充： if you are interested, you may watch these 2 etv to understand more but i think it is too difficult and not necessary yet for a form 1 student. But it is so good that a form 1 student interested to learn this topic. 2007-01-27 19:50:55 補充： http://webserver1.etvonline.tv/etv_c/digilibrary/archive.cfm?PROGRAM_REF_NBR=1295http://webserver1.etvonline.tv/etv_c/digilibrary/archive.cfm?PROGRAM_REF_NBR=1346
其他解答:
請問可否列出如何計算出X值的步驟?
發問:
(1.2926 - X) x 100000 = 2475/ X 更新: i'm just studying form 1, please show me the details. Thanks~
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最佳解答:(1.2926 - X) x 100000 = 2475/ X 1.2926-X=0.02475/X 1.2926X-X^2=0.02475 X^2-1.2926X+0.02475=0 X=1.273 or X=0.0194 if you are higher than Form 3, i think you could understand my steps, if not, please ask for more detail steps. 2007-01-27 19:50:30 補充： for this question, if not using programme of calculator, the only way to solve is using this formula:if ax^2 bx c=0, x=(-b 開方[b^2-4ac])/2a or x=(-b-開方[b^2-4ac])/2ain this case, a=1, b=-1.2926, c=0.02475so X=1.273 or X=0.0194 2007-01-27 19:50:47 補充： if you are interested, you may watch these 2 etv to understand more but i think it is too difficult and not necessary yet for a form 1 student. But it is so good that a form 1 student interested to learn this topic. 2007-01-27 19:50:55 補充： http://webserver1.etvonline.tv/etv_c/digilibrary/archive.cfm?PROGRAM_REF_NBR=1295http://webserver1.etvonline.tv/etv_c/digilibrary/archive.cfm?PROGRAM_REF_NBR=1346
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