標題:

H.C.F. & L.C.M.

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發問:

Pls. help to solve the below sums. Show the steps.1. It is know that the H.C.F. of a given number is 28 is 2. Find two possible values of the given number. 2. It is know that the L.C.M. of a given number is an 18 is 72. Find two possible values of the given number. 3. Subtract the sum of all... 顯示更多 Pls. help to solve the below sums. Show the steps. 1. It is know that the H.C.F. of a given number is 28 is 2. Find two possible values of the given number. 2. It is know that the L.C.M. of a given number is an 18 is 72. Find two possible values of the given number. 3. Subtract the sum of all the prime numbers between 20 & 30 from the sum of all the prime numbers between 10 & 20. What is the difference?

最佳解答:

1. Because The H.C.F of 28 and unknown is 2, so the unknown must be an even number that cannot divided by 4/7/14/28. So the number could be 2,6,10,18 etc. 2. The L.C.M of a number could be the product of two numbers. The answer could be 4,8 3. The difference = (11+13+17+19)-(23+29) = 60-52 = 8

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