標題:
F.2 Maths. - Please help!!!
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最佳解答:
2xy - 12 /x^2y^2 -12xy + 36 除 1/3x^y^2 - 19xy + 6 =2(xy-6)/(xy-6)^2 除 1/(3XY-1)(xy-6) =2/(xy-6) 乘 (3xy-1) (xy-6) =2(3xy-1) =6xy-2 解釋: 2xy - 12 /x^2y^2 -12xy + 36 除 1/3x^y^2 - 19xy + 6 =2(xy-6<抽個2出黎>(xy-6)^2<用(a+b)^2=a^2+2ab+b^2>除 1/(3XY-1)(xy-6)<用十字相乘法> =2/(xy-6)<約左個(xy-6)> 乘 (3xy-1)(xy-6)/1 <除分數要上下顛倒> =2(3xy-1) <約左個(xy-6)> =6xy-2 <乘返個2入去>
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F.2 Maths. - Please help!!!
發問:
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Simplify the following expressions:( 注: 份數 除份數) 2xy - 12 ------------------------ x^2y^2 -12xy + 36 除 1 -------------------------- 3x^y^2 - 19xy + 6最佳解答:
2xy - 12 /x^2y^2 -12xy + 36 除 1/3x^y^2 - 19xy + 6 =2(xy-6)/(xy-6)^2 除 1/(3XY-1)(xy-6) =2/(xy-6) 乘 (3xy-1) (xy-6) =2(3xy-1) =6xy-2 解釋: 2xy - 12 /x^2y^2 -12xy + 36 除 1/3x^y^2 - 19xy + 6 =2(xy-6<抽個2出黎>(xy-6)^2<用(a+b)^2=a^2+2ab+b^2>除 1/(3XY-1)(xy-6)<用十字相乘法> =2/(xy-6)<約左個(xy-6)> 乘 (3xy-1)(xy-6)/1 <除分數要上下顛倒> =2(3xy-1) <約左個(xy-6)> =6xy-2 <乘返個2入去>
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